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Description
do.call now this is pain...
foo <- \(x) x + 1
# x won't be obfuscated because it's on the
# right-hand side of call to list
do.call(foo, list(x = 41))
# the string literal "foo" refers to a function
# won't be obfuscated, it's treated as a string
do.call("foo", list(x = 41))Reactions are currently unavailable
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