Skip to content

do.call #14

@JohnCoene

Description

@JohnCoene

do.call now this is pain...

foo <- \(x) x + 1

# x won't be obfuscated because it's on the 
# right-hand side of call to list
do.call(foo, list(x = 41))

# the string literal "foo" refers to a function
# won't be obfuscated, it's treated as a string
do.call("foo", list(x = 41))

Metadata

Metadata

Assignees

Labels

wontfixThis will not be worked on

Type

Projects

No projects

Milestone

No milestone

Relationships

None yet

Development

No branches or pull requests

Issue actions