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34.在排序数组中查找元素的第一个和最后一个位置.py
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64 lines (61 loc) · 1.67 KB
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#
# @lc app=leetcode.cn id=34 lang=python
#
# [34] 在排序数组中查找元素的第一个和最后一个位置
#
# https://leetcode-cn.com/problems/find-first-and-last-position-of-element-in-sorted-array/description/
#
# algorithms
# Medium (37.59%)
# Likes: 212
# Dislikes: 0
# Total Accepted: 34.2K
# Total Submissions: 90.7K
# Testcase Example: '[5,7,7,8,8,10]\n8'
#
# 给定一个按照升序排列的整数数组 nums,和一个目标值 target。找出给定目标值在数组中的开始位置和结束位置。
#
# 你的算法时间复杂度必须是 O(log n) 级别。
#
# 如果数组中不存在目标值,返回 [-1, -1]。
#
# 示例 1:
#
# 输入: nums = [5,7,7,8,8,10], target = 8
# 输出: [3,4]
#
# 示例 2:
#
# 输入: nums = [5,7,7,8,8,10], target = 6
# 输出: [-1,-1]
#
#
class Solution(object):
def searchRange(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
def left_search(nums, target):
left=0
right=len(nums)-1
while left <= right:
mid=(left+right)/2
if nums[mid]<target:
left=mid+1
else:
right=mid-1
return left
def right_search(nums,target):
left=0
right=len(nums)-1
while left <= right :
mid = (left+right)/2
if nums[mid]>target:
right=mid-1
else:
left=mid+1
return right
l,r=left_search(nums, target),right_search(nums,target)
return [l,r] if l<=r else [-1,-1]