#import "NSString+LJExtension.h" ->

[hug2008]

• (NSString )lj_filterSpecialString:(NSString )string
  {
  // 这个语句对显示为 +86 138*********** 格式的不起作用的
  // 因为 +86 后面跟的空白根本不是空格
  string = [string stringByReplacingOccurrencesOfString:@" " withString:@""];
  ...........................
  return string;
  }

改进建议，使用数字搜索：

• (NSString *)lj_filterSpecialString:(NSString *)string
  {
  NSString *cnPhoneOrig = [string copy];
  if (0 == cnPhoneOrig.length)
  {
  return @"";
  }

  NSScanner *aScaner = [NSScanner scannerWithString:cnPhoneOrig];

  NSCharacterSet *aSetNumbers = [NSCharacterSet characterSetWithCharactersInString:@"0123456789"];

  NSString *cnPhone = @"";

  NSString *aNumber = nil;
  NSString *aOther = nil;

  while (![aScaner isAtEnd])
  {
  [aScaner scanUpToCharactersFromSet:aSetNumbers intoString:&aOther];

    [aScaner scanCharactersFromSet:aSetNumbers intoString:&aNumber];
    
    cnPhone = [cnPhone stringByAppendingString:aNumber];
  

  }

  if ([cnPhone hasPrefix:@"86"])
  {
  cnPhone = [cnPhone substringFromIndex:2];
  }

  if ([cnPhone hasPrefix:@"086"])
  {
  cnPhone = [cnPhone substringFromIndex:3];
  }

  return cnPhone;
  }