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Codecov Report❌ Patch coverage is
❌ Your patch check has failed because the patch coverage (0.00%) is below the target coverage (80.00%). You can increase the patch coverage or adjust the target coverage. Additional details and impacted files@@ Coverage Diff @@
## main #73 +/- ##
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- Coverage 80.28% 78.03% -2.26%
Complexity 74 74
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Files 13 13
Lines 208 214 +6
Branches 0 2 +2
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Hits 167 167
- Misses 41 47 +6
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PR DescriptionThis pull request enhances the Click to see moreKey Technical ChangesThe key technical changes involve the addition of the Architecture DecisionsThe Dependencies and InteractionsThis change only modifies the Risk ConsiderationsThe recursive implementation of the Notable Implementation DetailsThe |
![codecov-ai[bot]](https://avatars.githubusercontent.com/in/797565?s=60&v=4){kind=small}
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| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; | ||
| return n * this.factorial(n - 1); |
There was a problem hiding this comment.
The factorial method uses recursion which can lead to stack overflow for large inputs. Consider using an iterative implementation for better performance and to avoid potential stack overflow errors.
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| let result = 1; | |
| for (let i = 2; i <= n; i++) { | |
| result *= i; | |
| } | |
| return result; | |
| } |
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| absolute(number) { | ||
| return Math.abs(number); |
There was a problem hiding this comment.
Input validation is missing in the absolute method. You should verify that the input is a valid number to prevent unexpected behavior.
| absolute(number) { | |
| return Math.abs(number); | |
| absolute(number) { | |
| if (typeof number !== 'number' || isNaN(number)) { | |
| return NaN; | |
| } | |
| return Math.abs(number); | |
| } |
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| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; | ||
| return n * this.factorial(n - 1); |
There was a problem hiding this comment.
The factorial function lacks a check for large inputs which could cause performance issues or stack overflow. Consider adding an upper limit.
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (!Number.isInteger(n)) return NaN; | |
| if (n > 170) return Infinity; // JavaScript's maximum safe factorial | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| } |
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| absolute(number) { | ||
| return Math.abs(number); | ||
| } | ||
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| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; | ||
| return n * this.factorial(n - 1); |
There was a problem hiding this comment.
Missing JSDoc comments for the new methods. Adding documentation would improve code readability and maintainability.
| absolute(number) { | |
| return Math.abs(number); | |
| } | |
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| /** | |
| * Returns the absolute value of a number | |
| * @param {number} number - The input number | |
| * @returns {number} The absolute value | |
| */ | |
| absolute(number) { | |
| return Math.abs(number); | |
| } | |
| /** | |
| * Calculates the factorial of a non-negative integer | |
| * @param {number} n - The non-negative integer | |
| * @returns {number} The factorial value, or NaN for invalid inputs | |
| */ | |
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| } |
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| absolute(number) { | ||
| return Math.abs(number); | ||
| } | ||
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| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; | ||
| return n * this.factorial(n - 1); |
There was a problem hiding this comment.
Consider adding unit tests for the new methods to ensure they work as expected with various inputs, including edge cases.
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![seer-by-sentry[bot]](https://avatars.githubusercontent.com/in/801464?s=60&v=4){kind=small}
| absolute(number) { | ||
| return Math.abs(number); | ||
| } |
There was a problem hiding this comment.
Consider adding input validation to ensure the parameter is a number. The current implementation will pass through any input to Math.abs(), which may produce unexpected results for non-numeric inputs like strings or objects.
| absolute(number) { | |
| return Math.abs(number); | |
| } | |
| absolute(number) { | |
| if (typeof number !== 'number' || isNaN(number)) { | |
| throw new Error('Input must be a valid number'); | |
| } | |
| return Math.abs(number); | |
| } |
Did we get this right? 👍 / 👎 to inform future reviews.
| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; | ||
| return n * this.factorial(n - 1); | ||
| } |
There was a problem hiding this comment.
The recursive factorial implementation has potential performance and stack overflow issues for large values of n. Consider adding input validation for the upper bound and potentially implementing an iterative version for better performance and stack safety.
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| } | |
| factorial(n) { | |
| if (typeof n !== 'number' || !Number.isInteger(n)) { | |
| throw new Error('Input must be a valid integer'); | |
| } | |
| if (n < 0) return NaN; | |
| if (n > 170) throw new Error('Input too large, would cause overflow'); | |
| if (n <= 1) return 1; | |
| // Iterative approach for better performance | |
| let result = 1; | |
| for (let i = 2; i <= n; i++) { | |
| result *= i; | |
| } | |
| return result; | |
| } |
Did we get this right? 👍 / 👎 to inform future reviews.
| factorial(n) { | ||
| if (n < 0) return NaN; | ||
| if (n <= 1) return 1; |
There was a problem hiding this comment.
The factorial method should handle non-integer inputs more explicitly. Currently, it will attempt to calculate factorial for decimal numbers, which may not be the intended behavior. Consider checking if the input is an integer.
| factorial(n) { | |
| if (n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| factorial(n) { | |
| if (!Number.isInteger(n) || n < 0) return NaN; | |
| if (n <= 1) return 1; | |
| return n * this.factorial(n - 1); | |
| } |
Did we get this right? 👍 / 👎 to inform future reviews.
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